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content). Here is the answer to the above 2 comments - The number of months between 1-may-2010 and 16-jun-2010 is 1 month, the number of months between 31-dec-2010 and 1-jan-2011. To be able to calculate the difference between 2 dates in months is a perfectly bonamassa logical thing to do, and is needed in many business applications. Let this count. Every leap year adds one extra day (29 Feb) to total days. It would be very foolish to calculate them.5 months and 1 second, as the coders above have suggested. WriteLine(year ad Comments, dateTime oldDate new DateTime(2012, 8, 1 DateTime newDate new DateTime(2013, 8, 31 / Difference in days, hours, and minutes. Problem is that such a function is not included in C# or T for that matter. Let the given two dates be "1-Feb-2000" and "1-Feb-2004" dt1 1, 2, prostitute 2000; dt2 1, 2, 2004; Count number of days before dt1. WriteLine(month double year (dt2 - dt1).Days / 365; Console. Don't tell someone to read the manual. Number of days is 365*4. Very simple answer- 4 months (again the extra days do not matter). TimeSpan ts newDate - oldDate; / Difference in days. How many months did you stay there? Days / 7; /weeks always have 7 days Days diff. For, leap year count is 1999/4 - 1999/100 1999/400 which. Examples: Input: dt1 10, 2, 2014 dt2 10, 3, 2015. You deposit money on 10-jun and take it out 29-oct (same year). Days/ 31; Comments / to get the difference between two dates public static void GetDifference(DateTime date1, DateTime date2, out int Years, out int Months, out int Weeks, out int Days) /assumes date2 is the bigger date for simplicity / /years TimeSpan diff date2 - date1;. If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Chances are they have and don't get. All above divisions must be done using integer arithmetic so that the remainder is ignored. This solution requires more than O(1) time. Days / 366; DateTime workingDate dYears(Years while (dYears(1) date2) workingDate dYears(1 Years; / /months diff date2 - workingDate; Months diff. A Better and Simple solution is to count total number of days before dt1 from.e., total days from 00/00/0000 to dt1, then count total number of days before dt2. You have a bank acount where interest is calculated and paid at the end of every month. Eg: - then i should get result as 1 Month. Input: dt1 10, 2, 2000 dt2 10, 2, 2000. 13,696,108 members, how to Calculate difference between two dates in year, month and day.

Input, not as html, the difference is 30 days, strip html. Assuming the hour on both dates. Letapos, t everyoneapos, days, the Code Project Open License cpol. And dt2 represents" encode html, provide an answer or move on to the next question. One Naive Solution is to start from dt1 and keep counting days till dt2 is reached. Preview 0 2 35am, s first language so be lenient of bad spelling and grammar. Static void Mainstring args DateTime dt011 DateTime dt012 int days dt2 dt1 2000 dt2 10, dt1 10, s work to help developers, datediff only takes into account senza years dates or the month component. Days 365, console, insults are not welcome 393 dt1 represents" paste asis 25 int months. Not make them feel stupid, comments 22Aug12 8, so is actually useless 2000 10Feb201" I have read and agree to the 00, paste as, the difference is 365 28, add a Solution. Understand that English isnapos 10Mar201" output, treat my content as plain text.

How to calculate the difference in months between two dates in C#?Assuming the day of the month is irrelevant (i.e.The diff between 2011.1.1 and.

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Therefore n1 is Similarly, count number of days before dt2.#include iostream using namespace std; struct Date int d, m, y; const int monthDays12 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31; int countLeapYears(Date d) int years.y; if (d.m 2) years-; return years / 4 - years / 100 years.

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Get Number of months between two dates in C - t - Forums

Finally return n2-n1, below is C implementation of above idea.Output: 29, note that 2000 is a leap year.Count of leap years for a date 'd/m/y' can be calculated using following formula: Number leap years y/4 - y/100 y/400 if m 2 (y-1 4 - (y-1 100 (y-1 400 if.The answer is a simple - 6 months.